Norlan and All,
It turns out that I made a misstatement in the last e-mail. I
rechecked the original account
of the experiment and found that the suspension wire was composed of no.
24 piano wire. I don't
know how this would effect your speculation of there remaining some sort
of twist in the wire
since I am not a piano player and I am unaware if this is one of those
cases where the larger number
actually implies a smaller calibre wire or a larger calibre wire. I work
on a horse farm so, I am aware
at least that when it comes to some types of wires, the larger number
actually means the wire is not
as thick. I would imagine that the thicker the wire the more likely it
would be to find some bias from
the coiling of the wire as it was manufactured.
You have brought to mind a possible gap in my thinking whether it
turns out to be a factor or
not. Considering absolutely everything is sometimes essential to finding
out the truth about things.
I have always made the assumption that the suspension line was
pliable enough to the point that
it would uncoil perfectly straight and thus not have a bearing. You are
right that the plumbob probably
doesn't weigh as much as the total 4250 feet length of wire and in that
case the mere weight of the wire
itself probably will add to the likely hood that the wire will be
perfectly straight for the experiment.
My tendency though is to look at things from greater distances
though and even though
one might well believe that this is just something illusive concerning a
local influence there are
at least two other possibilities I wish to examine more closely.
I will mention some of them right now. Much has been said concerning
centrifugal force. Some
even mention it as an equaling factor in deciding what sort of
gravitational field exists within the
earth itself. As I pointed out in my forum message (Jan's web site)
quite a while back, centrifugal
force is only 1 part in 300 as strong as the gravitational force and that
is at its maximum at the equator.
Nevertheless when we are talking about as little a distance as we are
with the plumbob variance,
I believe that one has to investigate it in full so that it is either
counted in full or discarded.
I have this concept in mind that at each latitude, there is a
distinct and measurable
centrifugal force on the surface of the earth as well as 4250 feet below
the surface at the plumbob
site. I imagine I will just have to assume a perfectly spherical planet
even though we are aware
of the fact that the earth is flattened at the poles. There are
equations for finding the characteristics
of ellipses but I sort of doubt this accuracy compared to the oblateness
of the earth because I
believe that the surface curvature is not consistent.
Nevertheless, this doesn't nullify the calculations I have in
mind at all. This is chiefly because
we can attribute both a very similar aspect toward the exact center of
gravity from the tops of the
two mine shaft locations as well as the fact that any close comparison
between the measurement of
a circumference (radius times radius) and the chord value found by
employing the law of cosines
is virtually identical when one deals with angles of arc between this
gap, (the two different mine shafts).
My idea is to find for the value of the outward centrifugal force at the
plumbobs distance to the spine
or rotational axis of the planet and assign it a scalar force of such and
such an amount of centimeters
over an initial second of time. This will give me a figure that I can
then compare with the 980.665
cm/sec^2 mean surface acceleration that I will attribute to the force on
the hanging plumbob. Here it
gets a little sticky since I am only comparing a rate of acceleration
instead of an actual force behind
mass in motion.
There could reside an error at this point in my reasoning since
it stands to reason that a light
weight hanging by a sting on a merry-go-round that was turning rather
fast would probably be
influenced more by the same amount of angular momentum or centrifugal
force than an equal length
of string hanging from the same playground ride that was attached to a
much heavier object, so,
don't think that I haven't contemplated this point.
In my college days, I remember a specific problem in a
trigonometry class I took. There
were two draft horse applying 1000 pounds each to a plow. It was
practice in application of the
law of cosines and both horses were pulling the plow from 15 degree
different angles. The problem
proved that the actual total force being applied to the plow would thus
be roughly only 1931 pounds
instead of 2000 pounds of force due to the inefficiency of the angles the
effort was being made from.
The point of all this is that once I have the outward scalar of
centrifugal force, I can divide it in two
and apply it in the same mechanism as the plow horses to determine how
much of the original force
would be applied to the plumbob at the southern downward angle side of
the center vector
(to the exact center of gravity) that the plumbob line held.
My reasoning then is that since this amount of force will not
exceed 3.37 cm/sec^2 which is the
total C force for surface objects on the equator, then whatever pull is
made to the plumbob right angle
vector would be less than that and since it is so small, one can
literally assign it the same characteristics
as that of a near infinite circle out in space where there would be no y
axis degradation with a slight
perpendicular motion to the side. On very small circles, I would not be
justified in doing this.
After finding out the altered position of one plumbob I judge the
other one the same way, but since
the second one is placed hypothetically 4250 feet to the north of the
first, its angle to the center of the
planet will be slightly steeper in the Cartesian coordinate system. I
will then have a slightly different
C force, though arguably faintly so, and also a slightly different angle
center vector. I would then
determine if this difference could be instrumental in moving the plumbobs
even a minor or possibly
totally sufficient distance to make for the difference.
One error I also contemplate is that of the measurement of how
much force I calculated that the
plumbobs would have to have assigned to them to get the variance we do.
This presents us with a
seeming contradiction because I arrive at the force of acceleration I am
seeking to match by a comparison
of vector magnitudes. The length of the suspension line is 4250 feet.
The total deviance from the expected
result of the plumbobs is actually a little over a foot and a half.
Remember, 8.22 inches wider than the top
of the shaft ignores the fact that to be exactly parallel with the
suspension lines, we are still diverting from
the condition where we actually should be converging, so that is part of
the reason I seek about 21+ inches
in total. Anyway I compare this distance alongside the 4250 feet span
and as a ratio of the surface
acceleration, ( * 980.665) I see that only a comparative acceleration of
force of only about 0.3651
centimeters per second squared is needed. This is the only "BUG" I have
yet to figure out. You all have
probably seen those mathematical problems in school that show a stream of
water moving at 5 miles per
hour and assuming a constant rate of egress perpendicularly across by a
boat at 3 miles per hour renders
a magnitude of force using Pythagorus of the square of the two side
velocities or ( the square root of (5^2 + 3^2 )
or the square root of 34)
This is why judging gravitational force and therefore position
via the rate of acceleration is a bit dicey.
It is however how they judge the forces made by other heavenly bodies so
I don't believe that I have totally
fallen off the boat, but I must confess that some very careful thought is
still needed.
Another problem which I am thinking of rectifying is the fact
that all this lecture on centrifugal force may
be nullified if the mine shafts are positioned on the same exact latitude
line. I speculate that I could write a
routine for my ever growing computer program concerning hollow earth
matters that would do all these
calculations instantly and I could adjust several parameters at once.
Namely, the acceleration rate within a
planet, ( Rodney Cuff found out that in the Greenland ice hole
experiments that there was a drop in gravity as
one proceeded deeper into the planet) Secondly, I could provide a
latitude meter so that the user can examine
any and all latitudes that desire attention, and Thirdly, this
latitude would be not the position of either mine
shafts itself but exactly halfway between the two. One would then have
an angular swivel wheel input via a
computer mouse to see that actually this entire effect of spine radius
centrifugal force would increase along
the north south meridian and disappear all together when aligned with the
east and west latitude.
But guess what folks, this is only the beginning!
Since today is the 19th of January and thus my birthday, I will expound a
little further in the hopes that
many of you will choose to weigh in on this subject and send the list (or
me) a reaction.
As I stated earlier, I calculated in one reckoning method, that one only
needs a lateral acceleration of
0.3651 centimeters to account for the entire phenomenon. Since my spinal
acceleration idea currently
only appears (since I haven't done this yet) to account for a very few
centimeters of divergence, another
factor must be added to weigh this. We now deal exclusively with the
void of mass idea that others
as well as myself have held on this plumbob mystery. I will set the
plumbob back to its initial center
vector position. I will simply assume that different types of forces
quantified by the same type of
measurement (a scalar) are additive and so I can just add the spinal C
force in either afterward or
before.
I thought I was really barking up the wrong tree when I first
thought up this idea but here is what I
contend that I will try to do. We have a mirror condition going on in
two mine shafts. If we assume that
where there is less matter an object in our case the two bobs will bend
slightly away from the direction
that the void of mass is, which is of course located in the other mine
shaft. We for the present will assume
that the two mine shafts are equal in symmetry and depth. One problem in
all of this is that I have yet to
find out the exact nature of the Calumet or French mine sites. If the
shafts go deeper than the 4250 foot
level or there are a bunch of these mine shafts all around this second
idea becomes totally mute, however,
for the sake of sharing ideas I present my idea.
I am not sure just how to perform calculations that deal with the
attraction of two masses. It is not that
I don't know the formulas but when one is dealing with non planetary
scales, it is hard to get a handle on
how things work. So, instead of adding once all masses involved I will
add up all the resultant accelerations
that I expect would be needed to draw the plumbobs to the side in tandem
with the range of movement
already acquired with the spinal force. My idea is to count all of the
areas within the opposite mine shaft
plus all of the lateral adjoining passageway areas up to the point where
these regions do not overlap the
symmetry of the plumbobs own mine shaft areas.
I will assign a small chunk of matter to all of these areas and
most likely they will be cube shapes that
will be equivalent in volume to a small ball. I could simply assign to
each ball the general surface rock
density of the region and have a rough idea as to how much mass I would
be ultimately dealing with.
Then I would perform a binary sort of all member sets of chunks in the
opposite mine shafts and adjoining
tunnel. I would set a constant for acceleration as a high and 0.0 as a
low and then I would tally up the
distance and angle from the plumbob of all these areas and using the
inverse square law as well as
discounting all mass chunks that are not positioned along the right angle
perpendicular to the plumbob.
This means that for the set of mass chunks in the other mine shaft, those
near the surface would have their
additive acceleration values multiplied by the cosine of 45 degrees since
the shafts are 4250 feet apart and
also each is 4250 feet deep, we end with a 45 degree angle and so on and
so on for all other mass
chunks that have to be tallied. I reason that a perfectly lateral
attraction is as it is but those forces that would
inevitably draw the plumbob along a perpendicular angle to the suspension
wire, but, all other forces act
in concert along the same perpendicular even if they are not located
perpendicularly. So, that is why each
inverse square distance would be multiplied by the cosine value of its
aspect angle to the bob. ( I have done
something like this already in the gravity section of my hollow earth
program.)
One other point worth noting. I am judging this as an attractive
mass that is present and not as an
inversion of attraction in the opposite direction. It is as if I remove
all mass totally from the local environs
and apply the reverse of the actual situation which is a single
attraction to an L shaped mass lateral to it.
The binary loop performs until I reach a target acceleration
figure. If the amount of surface
acceleration by an individual chunk of matter can be found in this way,
all I have to do then is to judge
whether this amount of acceleration is harmonious with the weight and
density of these standard units
of matter which were tallied to attain the desired result of sway on the
plumbob. I frankly have never tried
anything quite like this before so it may take me some months of spare
time thought to even figure how to
go about it. I would compare this figure with larger massive bodies,
even planets and judge by this reckoning
if the figure I arrived at was in line with it.
Now comes the really interesting part! Lets assume that the
figure is grossly out of line with the
what it ought to be. In other words, the cause behind the full variance
of the plumbob is not yet know. Where
do we go now?
This is were my really imaginative idea comes into play, if
needed. Most have assumed that the plumbob
was either one of those unknowns without answer or that the answer was to
be had in the void of mass theory
but was pretty much unprovable. I know its a huge stretch, but I
endeavor to do just that. I actually came up
with this idea because of another idea that has been floating around.
That is the one where establishment types
teach that inside of a hollow shell planet structure, there would be
nothing but null gravity. I actually have already
written a computer program that proves that this is wrong, but in doing
so, I came up with what I term my own
pet unified theory on the hollow earth. It deals with a repulsive
central sun and not an attractive one and I believe
three things about such an arrangement.
1. A repulsive central star would be a better idea since it repels and
therefore
could never collide with the inside shell of the planet if any great
force pushed the central
star in the middle of our planet off center. In other words, things
would be self correcting.
2. A repulsive or negative core central sun would provide for a positive
gravitational field for flora
and fauna at the surface of the inner shell of a hollow planetary cavity,
and
3. Such repulsive forces that erase a null gravity condition which has
been a strike against the hollow
earth theory for many academics, or, adds to the somewhat weaker
gravitational field derived by
that calculations made in my computer program, WILL also keep repulsing
all the way out to the
outer surface of the planet and are in fact a third additive force which
will make up for any inadequacies
with the first two forces I have already accounted for.
You may state, rightfully so, that there is absolutely no
evidence of such a repulsive force here on
the outer earth's surface. Correct, as far as it goes, but then again if
one considers that the repulsive force
would be very much weakened by the time it made its way up to the surface
and being diminished by the
inverse square law, it just might be the case. I am obviously
insinuating that a repulsive force of gravity
would act over increasing distances in much the same as an attractive
force would being lessened
accordingly.
Another point is that since everything basically points to a
center of gravity that is congruent with
the center vector, the ether wind or anti gravitational force would
impact all objects hanging in line with
the center vector of attraction that the planet obviously exudes at a
perfect opposite angle and thus,
the only time such a force might be measured or noticed is when either a
combination of the spinal
C force and the void of mass forces acted as catalysts drawing the object
slightly off center vector so
that the ether wind, to coin a phrase, could exert a non symmetrical
force on a single side of the object.
Remember, if the suspension wire is held stationary and the bob is pulled
off of its normal perfect
alignment with the center vector, then all ether wind forces will gain an
oblique aspect to the alignment of
the wire and bob and thus provide the chance for its slight force to
finish the job of drawing the plumbobs
to the unexpected positions that have puzzled all of us.
THANKS FOR READING MY BRIEF AND LET ME KNOW IF YOU GUYS THINK THIS
WOULD BE A VALUABLE ADDITION TO HOLLOW EARTH SCIENCE!
···
________________________________________________________________
GET INTERNET ACCESS FROM JUNO!
Juno offers FREE or PREMIUM Internet access for less!
Join Juno today! For your FREE software, visit:
http://dl.www.juno.com/get/tagj.